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=-16H^2+46H+4
We move all terms to the left:
-(-16H^2+46H+4)=0
We get rid of parentheses
16H^2-46H-4=0
a = 16; b = -46; c = -4;
Δ = b2-4ac
Δ = -462-4·16·(-4)
Δ = 2372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2372}=\sqrt{4*593}=\sqrt{4}*\sqrt{593}=2\sqrt{593}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-2\sqrt{593}}{2*16}=\frac{46-2\sqrt{593}}{32} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+2\sqrt{593}}{2*16}=\frac{46+2\sqrt{593}}{32} $
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